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知乎，中文互联网高质量的问答社区和创作者聚集的原创内容平台，于 2011 年 1 月正式上线，以「让人们更好的分享知识、经验和见解，找到自己的解答」为品牌使命。 The confusing point here is that the formula $1^x = 1$ is not part of the definition of complex exponentiation, although it is an immediate consequence of the definition of natural number exponentiation. How do i convince someone that $1+1=2$ may not necessarily be true
I once read that some mathematicians provided a very length proof of $1+1=2$ There are infinitely many possible values for $1^i$, corresponding to different branches of the complex logarithm Can you think of some way to
I've noticed this matrix product pop up repeatedly and can't seem to de.
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In this case, adding 18 to the previous term in the sequence gives the next term In other words, an=a1+d (n−1) It's a fundamental formula not only in arithmetic but also in the whole of math Is there a proof for it or is it just assumed?
Intending on marking as accepted, because i'm no mathematician and this response makes sense to a commoner
However, i'm still curious why there is 1 way to permute 0 things, instead of 0 ways. 两边求和，我们有 ln (n+1)<1/1+1/2+1/3+1/4+……+1/n 容易的， \lim _ {n\rightarrow +\infty }\ln \left ( n+1\right) =+\infty ，所以这个和是无界的，不收敛。
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